If seven equal-width panels have a combined width of 31 1/2 FT, what is the width of one panel?

Prepare for the NCCR Boilermaker Test. Includes flashcards and multiple-choice questions with hints and detailed explanations to ensure your success. Gear up for your examination!

Multiple Choice

If seven equal-width panels have a combined width of 31 1/2 FT, what is the width of one panel?

Explanation:
When panels are the same width, the total width is seven times the width of one panel, so you divide the total by seven. 31 1/2 FT divided by 7 equals 4 1/2 FT for each panel. This checks out because 4 1/2 FT times seven equals 31 1/2 FT. The other options don’t fit because they would produce totals of 28 FT, 35 FT, or 26 1/4 FT when multiplied by seven.

When panels are the same width, the total width is seven times the width of one panel, so you divide the total by seven. 31 1/2 FT divided by 7 equals 4 1/2 FT for each panel. This checks out because 4 1/2 FT times seven equals 31 1/2 FT. The other options don’t fit because they would produce totals of 28 FT, 35 FT, or 26 1/4 FT when multiplied by seven.

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